Safe Haskell | None |
---|---|
Language | Haskell2010 |
Synopsis
- data SolveContext
- mustUnify :: SolveContext -> Bool
- canUnifyRecursive :: SolveContext -> Type -> Type -> Bool
- canUnify :: Bool -> Type -> Type -> Bool
- data Unification = Unification {}
- newtype OrdType = OrdType {
- getOrdType :: Type
- unzipNewWanteds :: Set Unification -> [(Unification, Ct)] -> ([Unification], [Ct])
Documentation
data SolveContext Source #
The context in which we're attempting to solve a constraint.
FunctionDef | In the context of a function definition. |
InterpreterUse Bool | In the context of running an interpreter. The |
Instances
Eq SolveContext Source # | |
Defined in Control.Effect.Plugin.Fundep.Unification (==) :: SolveContext -> SolveContext -> Bool # (/=) :: SolveContext -> SolveContext -> Bool # | |
Ord SolveContext Source # | |
Defined in Control.Effect.Plugin.Fundep.Unification compare :: SolveContext -> SolveContext -> Ordering # (<) :: SolveContext -> SolveContext -> Bool # (<=) :: SolveContext -> SolveContext -> Bool # (>) :: SolveContext -> SolveContext -> Bool # (>=) :: SolveContext -> SolveContext -> Bool # max :: SolveContext -> SolveContext -> SolveContext # min :: SolveContext -> SolveContext -> SolveContext # | |
Show SolveContext Source # | |
Defined in Control.Effect.Plugin.Fundep.Unification showsPrec :: Int -> SolveContext -> ShowS # show :: SolveContext -> String # showList :: [SolveContext] -> ShowS # |
mustUnify :: SolveContext -> Bool Source #
Depending on the context in which we're solving a constraint, we may or
may not want to force a unification of effects. For example, when defining
user code whose type is Eff (State Int) m => ...
, if we see
get :: Eff (State s) m => m s
,
we should unify s ~ Int
.
:: SolveContext | |
-> Type | wanted |
-> Type | given |
-> Bool |
Determine whether or not two effects are unifiable. This is nuanced.
There are several cases:
- [W] ∀ e1. e1 [G] ∀ e2. e2 Always fails, because we never want to unify two effects if effect names are polymorphic.
- [W] State s [G] State Int Always succeeds. It's safe to take our given as a fundep annotation.
- [W] State Int [G] State s (when the [G] is a given that comes from a type signature)
This should fail, because it means we wrote the type signature Eff
(State s) m => ...
, but are trying to use s
as an Int
. Clearly
bogus!
- [W] State Int [G] State s (when the [G] was generated by running an interpreter)
Sometimes OK, but only if the [G] is the only thing we're trying to solve right now. Consider the case:
runState 5 $ get @Int
Here we have [G] forall a. Num a => State a and [W] State Int. Clearly
the typechecking should flow "backwards" here, out of the row and into
the type of runState
.
What happens if there are multiple [G]s in scope for the same r
? Then
we'd emit multiple unification constraints for the same effect but with
different polymorphic variables, which would unify a bunch of effects
that shouldn't be!
data Unification Source #
A wrapper for two types that we want to say have been unified.
Instances
Eq Unification Source # | |
Defined in Control.Effect.Plugin.Fundep.Unification (==) :: Unification -> Unification -> Bool # (/=) :: Unification -> Unification -> Bool # | |
Ord Unification Source # | |
Defined in Control.Effect.Plugin.Fundep.Unification compare :: Unification -> Unification -> Ordering # (<) :: Unification -> Unification -> Bool # (<=) :: Unification -> Unification -> Bool # (>) :: Unification -> Unification -> Bool # (>=) :: Unification -> Unification -> Bool # max :: Unification -> Unification -> Unification # min :: Unification -> Unification -> Unification # |
Type
s don't have Eq
or Ord
instances by default, even though there
are functions in GHC that implement these operations. This newtype gives us
those instances.
unzipNewWanteds :: Set Unification -> [(Unification, Ct)] -> ([Unification], [Ct]) Source #
Filter out the unifications we've already emitted, and then give back the
things we should put into the S.Set Unification
, and the new constraints
we should emit.