lift-generics: GHC.Generics-based Language.Haskell.TH.Syntax.lift implementation

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This package provides a GHC.Generics-based genericLift function, which can be used for providing a Language.Haskell.TH.Syntax.lift implementation. See the documentation in the Language.Haskell.TH.Lift.Generics module to get started.

Credit goes to Matthew Pickering for suggesting this idea.


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Versions [RSS] 0.1, 0.1.1, 0.1.2, 0.1.3, 0.2, 0.2.1, 0.3
Change log CHANGELOG.md
Dependencies base (>=4.9 && <5), ghc-prim, template-haskell (>=2.11 && <2.23), th-compat (>=0.1 && <0.2) [details]
Tested with ghc ==8.0.2, ghc ==8.2.2, ghc ==8.4.4, ghc ==8.6.5, ghc ==8.8.4, ghc ==8.10.7, ghc ==9.0.2, ghc ==9.2.8, ghc ==9.4.8, ghc ==9.6.6, ghc ==9.8.2, ghc ==9.10.1
License BSD-3-Clause
Copyright (C) 2015-2017 Ryan Scott
Author Ryan Scott
Maintainer Ryan Scott <ryan.gl.scott@gmail.com>
Category Language
Home page https://github.com/RyanGlScott/lift-generics
Bug tracker https://github.com/RyanGlScott/lift-generics/issues
Source repo head: git clone https://github.com/RyanGlScott/lift-generics
Uploaded by ryanglscott at 2024-10-22T11:49:29Z
Distributions LTSHaskell:0.2.1, NixOS:0.2.1, Stackage:0.3
Reverse Dependencies 1 direct, 0 indirect [details]
Downloads 3769 total (51 in the last 30 days)
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Status Docs available [build log]
Last success reported on 2024-10-22 [all 1 reports]

Readme for lift-generics-0.3

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lift-generics

Haskell Programming Language Hackage Dependencies Haskell Programming Language BSD3 License Build Status

This package provides a GHC.Generics-based genericLift function, which can be used for providing a Language.Haskell.TH.Syntax.lift implementation. See the documentation in the Language.Haskell.TH.Lift.Generics module to get started.

Credit goes to Matthew Pickering for suggesting this idea.