antlr-haskell: A Haskell implementation of the ANTLR top-down parser generator

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Please see the README on Github at https://github.com/cronburg/antlr-haskell#readme and https://www.cronburg.com/2018/antlr-haskell-project/.


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Versions 0.1.0.0, 0.1.0.0, 0.1.0.1
Change log ChangeLog.md
Dependencies base (>=4.11 && <5), containers (==0.6.*), deepseq (==1.4.*), hashable (==1.2.*), haskell-src-meta (==0.8.*), mtl (==2.2.*), template-haskell (==2.14.*), text (==1.2.*), th-lift (>=0.7.11 && <0.8), transformers (==0.5.*), unordered-containers (==0.2.*) [details]
License BSD-3-Clause
Copyright MIT
Author Karl Cronburg & Matthew Ahrens
Maintainer karl@cs.tufts.edu
Category Library
Home page https://github.com/cronburg/antlr-haskell#readme
Bug tracker https://github.com/cronburg/antlr-haskell/issues
Source repo head: git clone https://github.com/cronburg/antlr-haskell
Uploaded by KarlCronburg at 2018-11-27T18:37:27Z

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Readme for antlr-haskell-0.1.0.0

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antlr-haskell

A Haskell implementation of ANTLR.

In implementing ANTLR we referenced the behavior of the original Java version (ANTLR4): The definitive ANTLR4 Reference. However we have taken much liberty in the design of this library compared to the workflow of the original Java version. In particular in implementing ANTLR for Haskell we have followed the following principles:

Build instructions

The library can be built with:

stack build # stack version 1.9.1.1
stack test antlr-haskell:simpl

Or with cabal-2.4.0.1 like:

cabal configure
cabal install --only-dependencies --enable-tests
cabal build
cabal test sexpression

sample grammar for ALL(*)

S -> Ac | Ad

A -> aA | b

ALL(*) Input/output examples

*Test.AllStarTests> parse ['a', 'b', 'c'] (NT 'S') atnEnv
(Just True, Node 'S' [Node 'A' [Leaf 'a', Node 'A' [Leaf 'b']], Leaf 'c'])
*Test.AllStarTests> parse ['b', 'd'] (NT 'S') atnEnv
(Just True, Node 'S' [Node 'A' [Leaf 'b'], Leaf 'd'])
*Test.AllStarTests> parse ['a', 'a', 'a', 'a', 'b', 'c'] (NT 'S') atnEnv
(Just True, Node 'S' [Node 'A' [Leaf 'a', Node 'A' [Leaf 'a', Node 'A' [Leaf 'a', Node 'A' [Leaf 'a', Node 'A' [Leaf 'b']]]]], Leaf 'c'])