acme-one: The identity element of package dependencies

[ acme, library, public-domain ] [ Propose Tags ]

Cabal package dependencies form a commutative monoid with an absorbing element. They satisfy the following axioms:

Associativity

For all dependencies a, b and c,

(a , b) , c = a , (b , c)

In fact, the Cabal syntax does not even allow you to use the parentheses for this reason.

Commutativity

For all dependencies a and b,

a , b = b , a
Identity element

For all dependencies a,

acme-one , a = a
a , acme-one = a

Depending on acme-one has no additional effect.

Absorbing element

For all dependencies a,

acme-zero , a = acme-zero
a , acme-zero = acme-zero

Depending on acme-zero in addition has the same effect as only depending on acme-zero.


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Versions [RSS] 0.0.1, 0.0.2
Dependencies None [details]
License LicenseRef-PublicDomain
Author Johan Kiviniemi <devel@johan.kiviniemi.name>
Maintainer Johan Kiviniemi <devel@johan.kiviniemi.name>
Category ACME
Home page https://github.com/ion1/acme-zero-one
Bug tracker https://github.com/ion1/acme-zero-one/issues
Source repo head: git clone https://github.com/ion1/acme-zero-one.git
Uploaded by ion at 2015-06-21T23:21:52Z
Distributions NixOS:0.0.2
Reverse Dependencies 1 direct, 0 indirect [details]
Downloads 1863 total (12 in the last 30 days)
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Status Docs not available [build log]
Last success reported on 2016-10-26 [all 9 reports]

Readme for acme-one-0.0.2

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acme-zero and acme-one

Cabal package dependencies form a commutative monoid with an absorbing element. They satisfy the following axioms:

  • Associativity

    For all dependencies a, b and c,

    (a , b) , c = a , (b , c)
    

    In fact, the Cabal syntax does not even allow you to use the parentheses for this reason.

  • Commutativity

    For all dependencies a and b,

    a , b = b , a
    
  • Identity element

    For all dependencies a,

    acme-one , a = a
    a , acme-one = a
    

    Depending on acme-one has no additional effect.

  • Absorbing element

    For all dependencies a,

    acme-zero , a = acme-zero
    a , acme-zero = acme-zero
    

    Depending on acme-zero in addition has the same effect as only depending on acme-zero.