Copyright | (C) 2017 Ryan Scott |
---|---|
License | BSD-style (see LICENSE) |
Maintainer | Ryan Scott |
Stability | experimental |
Portability | non-portable |
Safe Haskell | None |
Language | Haskell2010 |
Synopsis
- type ShowSing k = (forall z. Show (Sing (z :: k)) :: Constraint)
The ShowSing
type
type ShowSing k = (forall z. Show (Sing (z :: k)) :: Constraint) Source #
In addition to the promoted and singled versions of the Show
class that
singletons
provides, it is also useful to be able to directly define
Show
instances for singleton types themselves. Doing so is almost entirely
straightforward, as a derived Show
instance does 90 percent of the work.
The last 10 percent—getting the right instance context—is a bit tricky, and
that's where ShowSing
comes into play.
As an example, let's consider the singleton type for lists. We want to write an instance with the following shape:
deriving instance ??? => Show (Sing (x :: [k]))
To figure out what should go in place of ???
, observe that we require the
type of each field to also be Show
instances. In other words, we need
something like (Show (Sing (a :: k)))
. But this isn't quite right, as the
type variable a
doesn't appear in the instance head. In fact, this a
type is really referring to an existentially quantified type variable in the
SCons
constructor, so it doesn't make sense to try and use it like this.
Luckily, the QuantifiedConstraints
language extension provides a solution
to this problem. This lets you write a context of the form
(forall a. Show (Sing (a :: k)))
, which demands that there be an instance
for Show (Sing (a :: k))
that is parametric in the use of a
. Thus, our
final instance looks like:
deriving instance (forall a. Show (Sing (a :: k))) => Show (Sing (x :: [k]))
Because that quantified constraint is somewhat lengthy, we provide the
ShowSing
type synonym as a convenient shorthand. Thus, the above instance
is equivalent to:
deriving instance ShowSing k => Show (Sing (x :: [k]))
When singling a derived Show
instance, singletons
will also derive
a Show
instance for the corresponding singleton type using ShowSing
.
In other words, if you give singletons
a derived Show
instance, then
you'll receive the following in return:
- A promoted (
PShow
) instance - A singled (
SShow
) instance - A
Show
instance for the singleton type
What a bargain!
Orphan instances
Show (SSymbol s) Source # | |
Show (SNat n) Source # | |
Show (Sing z) Source # | |
(ShowSing a, ShowSing [a]) => Show (Sing z) Source # | |
ShowSing a => Show (Sing z) Source # | |
Show (Sing z) Source # | |
(ShowSing a, ShowSing b) => Show (Sing z) Source # | |
Show (Sing z) Source # | |
(ShowSing a, ShowSing b) => Show (Sing z) Source # | |
(ShowSing a, ShowSing b, ShowSing c) => Show (Sing z) Source # | |
(ShowSing a, ShowSing b, ShowSing c, ShowSing d) => Show (Sing z) Source # | |
(ShowSing a, ShowSing b, ShowSing c, ShowSing d, ShowSing e) => Show (Sing z) Source # | |
(ShowSing a, ShowSing b, ShowSing c, ShowSing d, ShowSing e, ShowSing f) => Show (Sing z) Source # | |
(ShowSing a, ShowSing b, ShowSing c, ShowSing d, ShowSing e, ShowSing f, ShowSing g) => Show (Sing z) Source # | |
Show (Sing z) Source # | |
ShowSing a => Show (Sing z) Source # | |
(ShowSing a, ShowSing [a]) => Show (Sing z) Source # | |