| Copyright | (c) 2016 Stephen Diehl (c) 2016-2018 Serokell (c) 2018-2021 Kowainik |
|---|---|
| License | MIT |
| Maintainer | Kowainik <xrom.xkov@gmail.com> |
| Stability | Stable |
| Portability | Portable |
| Safe Haskell | Safe |
| Language | Haskell2010 |
Relude.Monad
Description
Reexporting useful monadic stuff.
Synopsis
- module Relude.Monad.Reexport
- module Relude.Monad.Maybe
- module Relude.Monad.Either
- module Relude.Monad.Trans
- chainedTo :: Monad m => (a -> m b) -> m a -> m b
- infinitely :: Applicative f => f a -> f Void
Documentation
module Relude.Monad.Reexport
Reexports functions to work with different monads.
module Relude.Monad.Maybe
Provided new combinators to work with Maybe data type.
module Relude.Monad.Either
Provided new combinators to work with Either data type.
module Relude.Monad.Trans
Monad transformers functions and combinators.
chainedTo :: Monad m => (a -> m b) -> m a -> m b Source #
For chaining monadic operations in forward applications using (&)
Named version of =<<.
>>>Just [ 1 :: Int ] & chainedTo (viaNonEmpty head)Just 1>>>Nothing & chainedTo (viaNonEmpty head)Nothing
Since: 0.5.0
infinitely :: Applicative f => f a -> f Void Source #
Repeat a monadic action indefinitely.
This is a more type safe version of forever, which has a convinient
but unsafe type.
Consider the following two examples. In the getIntForever functions, it
falsely expects Int as the result of the forever function. But it would need
to wait *forever* to get that, and this mistake won't be caught by the type
system and compiler:
getIntForever :: IO Int
getIntForever = do
i <- forever $ do ...
pure i
In contrast, using infinitely instead of forever in foo is a type error.
Since: 1.0.0.0