lca-0.4: O(log n) persistent online lowest common ancestor search without preprocessing
Copyright(C) 2011-2015 Edward Kmett
LicenseBSD-style (see the file LICENSE)
MaintainerEdward Kmett <ekmett@gmail.com>
Stabilityexperimental
Portabilityportable
Safe HaskellSafe-Inferred
LanguageHaskell2010

Data.LCA.Online

Description

Provides online calculation of the the lowest common ancestor in O(log h) by compressing the spine of a Path using a skew-binary random access list.

This library implements the technique described in my talk

http://www.slideshare.net/ekmett/skewbinary-online-lowest-common-ancestor-search

to improve the known asymptotic bounds on both online lowest common ancestor search

http://en.wikipedia.org/wiki/Lowest_common_ancestor

and the online level ancestor problem:

http://en.wikipedia.org/wiki/Level_ancestor_problem

Algorithms used here assume that the key values chosen for k are globally unique.

Synopsis

Documentation

data Path a Source #

Compressed paths using skew binary random access lists

Instances

Instances details
Functor Path Source # 
Instance details

Defined in Data.LCA.Online

Methods

fmap :: (a -> b) -> Path a -> Path b #

(<$) :: a -> Path b -> Path a #

Foldable Path Source # 
Instance details

Defined in Data.LCA.Online

Methods

fold :: Monoid m => Path m -> m #

foldMap :: Monoid m => (a -> m) -> Path a -> m #

foldMap' :: Monoid m => (a -> m) -> Path a -> m #

foldr :: (a -> b -> b) -> b -> Path a -> b #

foldr' :: (a -> b -> b) -> b -> Path a -> b #

foldl :: (b -> a -> b) -> b -> Path a -> b #

foldl' :: (b -> a -> b) -> b -> Path a -> b #

foldr1 :: (a -> a -> a) -> Path a -> a #

foldl1 :: (a -> a -> a) -> Path a -> a #

toList :: Path a -> [a] #

null :: Path a -> Bool #

length :: Path a -> Int #

elem :: Eq a => a -> Path a -> Bool #

maximum :: Ord a => Path a -> a #

minimum :: Ord a => Path a -> a #

sum :: Num a => Path a -> a #

product :: Num a => Path a -> a #

Traversable Path Source # 
Instance details

Defined in Data.LCA.Online

Methods

traverse :: Applicative f => (a -> f b) -> Path a -> f (Path b) #

sequenceA :: Applicative f => Path (f a) -> f (Path a) #

mapM :: Monad m => (a -> m b) -> Path a -> m (Path b) #

sequence :: Monad m => Path (m a) -> m (Path a) #

Read a => Read (Path a) Source # 
Instance details

Defined in Data.LCA.Online

Show a => Show (Path a) Source # 
Instance details

Defined in Data.LCA.Online

Methods

showsPrec :: Int -> Path a -> ShowS #

show :: Path a -> String #

showList :: [Path a] -> ShowS #

lca :: Path a -> Path b -> Path a Source #

O(log h) Compute the lowest common ancestor of two paths.

>>> let fromList' = fromList . map (flip (,) ())
>>> length (lca (fromList' [1, 2, 3, 4, 5, 6]) (fromList' [7, 8, 3, 4, 5, 6]))
4

cons :: Int -> a -> Path a -> Path a Source #

O(1) Invariant: most operations assume that the keys k are globally unique

Extend the Path with a new node ID and value.

uncons :: Path a -> Maybe (Int, a, Path a) Source #

O(1) Extract the node ID and value from the newest node on the Path.

view :: Path a -> View Path a Source #

O(1) Extract the node ID and value from the newest node on the Path, slightly faster than uncons.

null :: Path a -> Bool Source #

O(1) Returns True iff the path is empty.

length :: Path a -> Int Source #

O(1) Determine the length of a Path.

isAncestorOf :: Path a -> Path b -> Bool Source #

O(log h) xs isAncestorOf ys holds when xs is a prefix starting at the root of Path ys.

keep :: Int -> Path a -> Path a Source #

O(log (h - k)) to keep k elements of Path of length h

This solves the online version of the "level ancestor problem" with no preprocessing in O(log h) time, improving known complexity bounds.

http://en.wikipedia.org/wiki/Level_ancestor_problem

drop :: Int -> Path a -> Path a Source #

O(log k) to drop k elements from a Path

traverseWithKey :: Applicative f => (Int -> a -> f b) -> Path a -> f (Path b) Source #

Traverse a Path with access to the node IDs.

toList :: Path a -> [(Int, a)] Source #

Convert a Path to a list of (ID, value) pairs.

fromList :: [(Int, a)] -> Path a Source #

Build a Path from a list of (ID, value) pairs.

(~=) :: Path a -> Path b -> Bool infix 4 Source #

O(1) Compare to see if two trees have the same root key