Copyright | (c) 2011 Daniel Fischer |
---|---|
License | MIT |
Maintainer | Daniel Fischer <daniel.is.fischer@googlemail.com> |
Safe Haskell | None |
Language | Haskell2010 |
Various functions related to prime factorisation.
Many of these functions use the prime factorisation of an Integer
.
If several of them are used on the same Integer
, it would be inefficient
to recalculate the factorisation, hence there are also functions working
on the canonical factorisation, these require that the number be positive
and in the case of the Carmichael function that the list of prime factors
with their multiplicities is ascending.
Synopsis
- factorise :: Integer -> [(Integer, Word)]
- defaultStdGenFactorisation :: StdGen -> Integer -> [(Integer, Word)]
- stepFactorisation :: Integer -> [(Integer, Word)]
- factorise' :: Integer -> [(Integer, Word)]
- defaultStdGenFactorisation' :: StdGen -> Integer -> [(Integer, Word)]
- trialDivisionTo :: Integer -> Integer -> [(Integer, Word)]
- smallFactors :: Integer -> Integer -> ([(Integer, Word)], Maybe Integer)
- stdGenFactorisation :: Maybe Integer -> StdGen -> Maybe Int -> Integer -> [(Integer, Word)]
- curveFactorisation :: forall g. Maybe Integer -> (Integer -> Bool) -> (Integer -> g -> (Integer, g)) -> g -> Maybe Int -> Integer -> [(Integer, Word)]
- montgomeryFactorisation :: KnownNat n => Word -> Word -> Mod n -> Maybe Integer
Factorisation functions
Factorisation of Integer
s by the elliptic curve algorithm after Montgomery.
The algorithm is explained at
http://programmingpraxis.com/2010/04/23/modern-elliptic-curve-factorization-part-1/
and
http://programmingpraxis.com/2010/04/27/modern-elliptic-curve-factorization-part-2/
The implementation is not very optimised, so it is not suitable for factorising numbers with several huge prime divisors. However, factors of 20-25 digits are normally found in acceptable time. The time taken depends, however, strongly on how lucky the curve-picking is. With luck, even large factors can be found in seconds; on the other hand, finding small factors (about 12-15 digits) can take minutes when the curve-picking is bad.
Given enough time, the algorithm should be able to factor numbers of 100-120 digits, but it is best suited for numbers of up to 50-60 digits.
factorise :: Integer -> [(Integer, Word)] Source #
produces the prime factorisation of factorise
nn
.
is
an error and the factorisation of factorise
01
is empty. Uses a StdGen
produced in
an arbitrary manner from the bit-pattern of n
.
Warning: there are no guarantees of any particular order of prime factors, do not expect them to be ascending. E. g.,
>>>
factorise 10251562501
[(101701,1),(100801,1)]
defaultStdGenFactorisation :: StdGen -> Integer -> [(Integer, Word)] Source #
first strips off all small prime factors and then,
if the factorisation is not complete, proceeds to curve factorisation.
For negative numbers, a factor of defaultStdGenFactorisation
-1
is included, the factorisation of 1
is empty. Since 0
has no prime factorisation, a zero argument causes
an error.
stepFactorisation :: Integer -> [(Integer, Word)] Source #
is like stepFactorisation
factorise'
, except that it doesn't use a
pseudo random generator but steps through the curves in order.
This strategy turns out to be surprisingly fast, on average it doesn't
seem to be slower than the StdGen
based variant.
factorise' :: Integer -> [(Integer, Word)] Source #
Like factorise
, but without input checking, hence n > 1
is required.
defaultStdGenFactorisation' :: StdGen -> Integer -> [(Integer, Word)] Source #
Like defaultStdGenFactorisation
, but without input checking, so
n
must be larger than 1
.
Trial division
trialDivisionTo :: Integer -> Integer -> [(Integer, Word)] Source #
produces a factorisation of trialDivisionTo
bound nn
using the
primes <= bound
. If n
has prime divisors > bound
, the last entry
in the list is the product of all these. If n <= bound^2
, this is a
full factorisation, but very slow if n
has large prime divisors.
Partial factorisation
smallFactors :: Integer -> Integer -> ([(Integer, Word)], Maybe Integer) Source #
finds all prime divisors of smallFactors
bound nn > 1
up to bound
by trial division and returns the
list of these together with their multiplicities, and a possible remaining factor which may be composite.
:: Maybe Integer | Lower bound for composite divisors |
-> StdGen | Standard PRNG |
-> Maybe Int | Estimated number of digits of smallest prime factor |
-> Integer | The number to factorise |
-> [(Integer, Word)] | List of prime factors and exponents |
A wrapper around curveFactorisation
providing a few default arguments.
The primality test is bailliePSW
, the prng
function - naturally -
randomR
. This function also requires small prime factors to have been
stripped before.
:: Maybe Integer | Lower bound for composite divisors |
-> (Integer -> Bool) | A primality test |
-> (Integer -> g -> (Integer, g)) | A PRNG |
-> g | Initial PRNG state |
-> Maybe Int | Estimated number of digits of the smallest prime factor |
-> Integer | The number to factorise |
-> [(Integer, Word)] | List of prime factors and exponents |
curveFactorisation
is the driver for the factorisation. Its performance (and success)
can be influenced by passing appropriate arguments. If you know that n
has no prime divisors
below b
, any divisor found less than b*b
must be prime, thus giving Just (b*b)
as the
first argument allows skipping the comparatively expensive primality test for those.
If n
is such that all prime divisors must have a specific easy to test for structure, a
custom primality test can improve the performance (normally, it will make very little
difference, since n
has not many divisors, and many curves have to be tried to find one).
More influence has the pseudo random generator (a function prng
with 6 <= fst (prng k s) <= k-2
and an initial state for the PRNG) used to generate the curves to try. A lucky choice here can
make a huge difference. So, if the default takes too long, try another one; or you can improve your
chances for a quick result by running several instances in parallel.
curveFactorisation
n
requires that small (< 100000) prime factors of n
have been stripped before. Otherwise it is likely to cycle forever. When in doubt,
use defaultStdGenFactorisation
.
curveFactorisation
is unlikely to succeed if n
has more than one (really) large prime factor.
Single curve worker
montgomeryFactorisation :: KnownNat n => Word -> Word -> Mod n -> Maybe Integer Source #
tries to find a factor of montgomeryFactorisation
n b1 b2 sn
using the
curve and point determined by the seed s
(6 <= s < n-1
), multiplying the
point by the least common multiple of all numbers <= b1
and all primes
between b1
and b2
. The idea is that there's a good chance that the order
of the point in the curve over one prime factor divides the multiplier, but the
order over another factor doesn't, if b1
and b2
are appropriately chosen.
If they are too small, none of the orders will probably divide the multiplier,
if they are too large, all probably will, so they should be chosen to fit
the expected size of the smallest factor.
It is assumed that n
has no small prime factors.
The result is maybe a nontrivial divisor of n
.