Similar to toListOf, but returning a Vector.

>>> toVectorOf each (8,15) == Vector.fromList [8,15]
True

Convert a list to a Vector (or back)

>>> [1,2,3] ^. vector == Vector.fromList [1,2,3]
True

>>> [1,2,3] ^. vector % re vector
[1,2,3]

>>> Vector.fromList [0,8,15] ^. re vector % vector == Vector.fromList [0,8,15]
True

Convert a Vector to a version that doesn't retain any extra memory.

sliced i n provides a Lens that edits the n elements starting at index i from a Lens.

This is only a valid Lens if you do not change the length of the resulting Vector.

Attempting to return a longer or shorter vector will result in violations of the Lens laws.

>>> Vector.fromList [1..10] ^. sliced 2 5 == Vector.fromList [3,4,5,6,7]
True

>>> (Vector.fromList [1..10] & sliced 2 5 % mapped .~ 0) == Vector.fromList [1,2,0,0,0,0,0,8,9,10]
True

This Traversal will ignore any duplicates in the supplied list of indices.

>>> toListOf (ordinals [1,3,2,5,9,10]) $ Vector.fromList [2,4..40]
[4,8,6,12,20,22]