Documentation

Move a Case-decomposition from the subject of a Case-decomposition to the alternatives

Remove non-reachable alternatives. For example, consider:

data STy ty where
  SInt :: Int -> STy Int
  SBool :: Bool -> STy Bool

f :: STy ty -> ty
f (SInt b) = b + 1
f (SBool True) = False
f (SBool False) = True
{-# NOINLINE f #-}

g :: STy Int -> Int
g = f

f is always specialized on STy Int. The SBool alternatives are therefore unreachable. Additional information can be found at: https://github.com/clash-lang/clash-compiler/pull/465

Flatten ridiculous case-statements generated by GHC

For case-statements in haskell of the form:

f :: Unsigned 4 -> Unsigned 4
f x = case x of
  0 -> 3
  1 -> 2
  2 -> 1
  3 -> 0

GHC generates Core that looks like:

f = \(x :: Unsigned 4) -> case x == fromInteger 3 of
                            False -> case x == fromInteger 2 of
                              False -> case x == fromInteger 1 of
                                False -> case x == fromInteger 0 of
                                  False -> error "incomplete case"
                                  True  -> fromInteger 3
                                True -> fromInteger 2
                              True -> fromInteger 1
                            True -> fromInteger 0

Which would result in a priority decoder circuit where a normal decoder circuit was desired.

This transformation transforms the above Core to the saner:

f = \(x :: Unsigned 4) -> case x of
       _ -> error "incomplete case"
       0 -> fromInteger 3
       1 -> fromInteger 2
       2 -> fromInteger 1
       3 -> fromInteger 0

Lift the let-bindings out of the subject of a Case-decomposition

Tries to eliminate existentials by using heuristics to determine what the existential should be. For example, consider Vec:

data Vec :: Nat -> Type -> Type where Nil :: Vec 0 a Cons x xs :: a -> Vec n a -> Vec (n + 1) a

Thus, null (annotated with existentials) could look like:

null :: forall n . Vec n Bool -> Bool null v = case v of Nil {n ~ 0} -> True Cons {n1:Nat} {n~n1+1} (x :: a) (xs :: Vec n1 a) -> False

When it's applied to a vector of length 5, this becomes:

null :: Vec 5 Bool -> Bool null v = case v of Nil {5 ~ 0} -> True Cons {n1:Nat} {5~n1+1} (x :: a) (xs :: Vec n1 a) -> False

This function solves n1 and replaces every occurrence with its solution. A very limited number of solutions are currently recognized: only adds (such as in the example) will be solved.