Safe Haskell | None |
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Language | Haskell2010 |
Documentation
Orphan instances
IndexHdr s x0 i0 us (BS1 Last O) cs c is (EdgeBoundary C) => AddIndexDense s ((:.) us (BS1 Last O)) ((:.) cs c) ((:.) is (EdgeBoundary C)) Source # | TODO 18.2.2017 added |
IndexHdr s x0 i0 us (BS1 Last I) cs c is (EdgeBoundary C) => AddIndexDense s ((:.) us (BS1 Last I)) ((:.) cs c) ((:.) is (EdgeBoundary C)) Source # | TODO 18.2.2017 added |
IndexHdr s x0 i0 us (BS1 First O) cs c is (EdgeBoundary C) => AddIndexDense s ((:.) us (BS1 First O)) ((:.) cs c) ((:.) is (EdgeBoundary C)) Source # | TODO 17.2.2017 added |
IndexHdr s x0 i0 us (BS1 First I) cs c is (EdgeBoundary C) => AddIndexDense s ((:.) us (BS1 First I)) ((:.) cs c) ((:.) is (EdgeBoundary C)) Source # | TODO 17.2.2017 added |
IndexHdr s x0 i0 us (BS1 Last I) cs c is (EdgeBoundary I) => AddIndexDense s ((:.) us (BS1 Last I)) ((:.) cs c) ((:.) is (EdgeBoundary I)) Source # | Generate all possible bitsets until |
IndexHdr s x0 i0 us (BS1 First I) cs c is (EdgeBoundary I) => AddIndexDense s ((:.) us (BS1 First I)) ((:.) cs c) ((:.) is (EdgeBoundary I)) Source # | Given indices that index _only_ the current edge The |
IndexHdr s x0 i0 us (BS1 k I) cs c is (Boundary k I) => AddIndexDense s ((:.) us (BS1 k I)) ((:.) cs c) ((:.) is (Boundary k I)) Source # | A single |
IndexHdr s x0 i0 us (BS1 k I) cs c is (Unit I) => AddIndexDense s ((:.) us (BS1 k I)) ((:.) cs c) ((:.) is (Unit I)) Source # | A |
IndexHdr s x0 i0 us (BS1 k I) cs c is (BS1 k O) => AddIndexDense s ((:.) us (BS1 k I)) ((:.) cs c) ((:.) is (BS1 k O)) Source # | |
IndexHdr s x0 i0 us (BS1 k O) cs c is (BS1 k O) => AddIndexDense s ((:.) us (BS1 k O)) ((:.) cs c) ((:.) is (BS1 k O)) Source # | For the inside case, we try all possible boundaries for TODO 17.2.2017 added |
IndexHdr s x0 i0 us (BS1 k I) cs c is (BS1 k I) => AddIndexDense s ((:.) us (BS1 k I)) ((:.) cs c) ((:.) is (BS1 k I)) Source # | Since there is only one boundary, it doesn't matter if Given the outer (set,bnd) system, we try all boundaries α for
(set-bnd,α) for the smaller set TODO After this case we should only allow TODO we should try to statically assure that TODO kind-of hacked and should be written in a better way |