Safe Haskell | Safe |
---|---|
Language | Haskell2010 |
Set
partial functions. Import as:
import qualified RIO.Set.Partial as Set'
Indexed
findIndex :: Ord a => a -> Set a -> Int #
O(log n). Return the index of an element, which is its zero-based
index in the sorted sequence of elements. The index is a number from 0 up
to, but not including, the size
of the set. Calls error
when the element
is not a member
of the set.
findIndex 2 (fromList [5,3]) Error: element is not in the set findIndex 3 (fromList [5,3]) == 0 findIndex 5 (fromList [5,3]) == 1 findIndex 6 (fromList [5,3]) Error: element is not in the set
Since: containers-0.5.4
O(log n). Retrieve an element by its index, i.e. by its zero-based
index in the sorted sequence of elements. If the index is out of range (less
than zero, greater or equal to size
of the set), error
is called.
elemAt 0 (fromList [5,3]) == 3 elemAt 1 (fromList [5,3]) == 5 elemAt 2 (fromList [5,3]) Error: index out of range
Since: containers-0.5.4
deleteAt :: Int -> Set a -> Set a #
O(log n). Delete the element at index, i.e. by its zero-based index in
the sorted sequence of elements. If the index is out of range (less than zero,
greater or equal to size
of the set), error
is called.
deleteAt 0 (fromList [5,3]) == singleton 5 deleteAt 1 (fromList [5,3]) == singleton 3 deleteAt 2 (fromList [5,3]) Error: index out of range deleteAt (-1) (fromList [5,3]) Error: index out of range
Since: containers-0.5.4
Min/Max
deleteFindMin :: Set a -> (a, Set a) #
O(log n). Delete and find the minimal element.
deleteFindMin set = (findMin set, deleteMin set)
deleteFindMax :: Set a -> (a, Set a) #
O(log n). Delete and find the maximal element.
deleteFindMax set = (findMax set, deleteMax set)